Disjunktive Normalform f(x1,x2,x3) = ((not x1) and x2 and (not x3)) or (x1 and x2 and (not x3)) or (x1 and x2 and x3)
Kojunktive Normalform f(x1,x2,x3) = (x1 or x2 or x3) and (x1 or x2 or (not x3)) and (x1 or (not x2) or (not x3)) and ((not x1) or x2 or x3) and ((not x1) or x2 or (not x3))
x3 and x2 and (not x1) and x0 or
x3 and (not x2) and x1 and x0 or
x3 and (not x2) and (not x1) and x0 or
(not x3) and x2 and x0 or
x3 and x2 and x1
x3 x2 x1 x0 f
0 0 0 0 0
1 0 0 0 1
2 0 0 1 0
3 0 0 1 1
4 0 1 0 0
5 0 1 0 1 1
6 0 1 1 0
7 0 1 1 1 1
8 1 0 0 0
9 1 0 0 1 1
10 1 0 1 0
11 1 0 1 1 1
12 1 1 0 0
13 1 1 0 1 1
14 1 1 1 0 1
15 1 1 1 1 1
Gruppe 0, keine 1
Gruppe 1, eine 1
Gruppe 2, zwei 1en
x3 x2 x1 x0 f
5 0 1 0 1 1 *
9 1 0 0 1 1 *
Gruppe 3, drei 1en
x3 x2 x1 x0 f
7 0 1 1 1 1 *
11 1 0 1 1 1 *
13 1 1 0 1 1 *
14 1 1 1 0 1 *
Gruppe 4, 4 1en
x3 x2 x1 x0 f
15 1 1 1 1 1 *
5, 7 *
9, 11 *
9, 13 *
7, 15
11, 15 *
13, 15 *
14, 15
5, 7 0 1 - 1
9, 11 1 0 - 1
9, 13 1 - 0 1
7, 15 - 1 1 1
11, 15 1 - 1 1
13, 15 1 1 - 1
14, 15 1 1 1 -
5, 7, 13, 15
9, 11, 13, 15
9, 13, 11, 15
5, 7, 13, 15 1 0 - 1
9, 11, 13, 15 1 - - 1
9, 13, 11, 15 1 - - 1
f(x3,x2,x1,x0) = (7, 15) or (14, 15)
5, 7, 9, 11, 13, 14, 15
7, 14 * *
14, 15 * *
