Wo es eindeutig erscheint

Die Zweier-Potenzen

$$1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, \dots$$

soll heissen:

wert	2er-potenz
$$1$$	$$2^0$$
$$2$$	$$2^1$$
$$4$$	$$2^2$$
$$8$$	$$2^3$$
$$16$$	$$2^4$$
$$32$$	$$2^5$$
$$64$$	$$2^6$$
$$128$$	$$2^7$$
$$256$$	$$2^8$$
$$512$$	$$2^9$$
$$1024$$	$$2^10$$
$$2048$$	$$2^11$$
$$4096$$	$$2^12$$
$$8192$$	$$2^13$$
...	...

d.h.

$$y$$	2er-potenz	$$log_2(y) = ld(y)$$
$$1$$	$$2^0$$	$$ld(1) = 0$$
$$2$$	$$2^1$$	$$ld(2) = 1$$
$$4$$	$$2^2$$	$$ld(4) = 2$$
$$8$$	$$2^3$$	$$ld(8) = 3$$
$$16$$	$$2^4$$	$$ld(16) = 4$$
$$32$$	$$2^5$$	$$ld(32) = 5$$
$$64$$	$$2^6$$	$$ld(64) = 6$$
$$128$$	$$2^7$$	$$ld(128) = 7$$
$$256$$	$$2^8$$	$$ld(256) = 8$$
$$512$$	$$2^9$$	$$ld(512) = 9$$
$$1024$$	$$2^10$$	$$ld(1024) = 10$$
$$2048$$	$$2^11$$	$$ld(2048) = 11$$
$$4096$$	$$2^12$$	$$ld(4096) = 12$$
$$8192$$	$$2^13$$	$$ld(8192) = 13$$
...	...

ebenso mit 10

$$y$$	10er-potenz	$$log_10(y) = lg(y)$$
$$1$$	$$10^0$$	$$lg(1) = 0$$
$$10$$	$$10^1$$	$$lg(10) = 1$$
$$100$$	$$10^2$$	$$lg(100) = 2$$
$$1000$$	$$10^3$$	$$lg(1000) = 3$$
$$10000$$	$$10^4$$	$$lg(10000) = 4$$
$$100000$$	$$10^5$$	$$lg(100000) = 5$$
$$1000000$$	$$10^6$$	$$lg(1000000) = 6$$
$$10000000$$	$$10^7$$	$$lg(10000000) = 7$$
$$100000000$$	$$10^8$$	$$lg(100000000) = 8$$
...	...

Es gibt den

$$log_a, log_{10} := lg, log_2 := ld, log_e := ln$$